Webf = focal length. • ( 5 votes) santhosh prabahar 5 years ago If you did this problem using the equation 1/f=1/v-1/u, you would get the answer as 6 cm. According to the same sign convention using which the above mentioned formula was derived, the answer 6 cm means the same as -6 cm when viewed from different sign conventions. WebAccording to the lens maker's formula, 1 f = ( n 2 n 1 − 1) ( 1 R 1 − 1 R 2), Here, n 2 is the refractive index of the lens and n 1 is the refractive index of the medium from which the light is incident on the lens. The medium …
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WebMar 15, 2024 · It is used to manufacture lenses of the desired focal length. Lens Maker’s Formula is given as 1 f = (v − 1)( 1 R1 − 1 R2) Where v is the refractive index of the material. f is the focal length. R1 is the radius of curvature of the first lens. R2 is the radius of curvature of the second lens. Now, as per the Power of a Lens Formula, P = 1/f WebNov 8, 2024 · Notice that while the focal length of a reflector is shorter than the radius of the mirror, for a refractor it is longer. So Equation 4.4.4 can be written in terms of the focal length as: n1 s + n2 s ′ = n2 f The ray traces of the other three cases look different from case 1: Figure 4.4.5 – Image of a Point on the Optical Axis – Picture (Case 2) cylinder shaped cells
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WebHow do you find the radius of curvature from the focal length and refractive index? Analytically, the focal length is described by the lens maker's equation: 1/f = (n - 1)(1/R 1 + 1/R 2), where R 1 and R 2 are the radii of curvature, f is the focal length, and n is the index of refraction. Verify that your earlier measurements are consistent ... Web1 f = ( n − 1) ( 1 R 1 − 1 R 2) where, f is the focal length (half the radius of curvature) n is the refractive index of the material used R1 is the radius of curvature of sphere 1 R2 is … WebApr 2, 2024 · Focal length f: 1 f = ( μ − 1) ( 1 R 1 − 1 R 2), where μ is the refractive index, R 1 is the radius of curvature of the surface close to the object, and, R 2 is the radius of curvature of the surface farther away from the object. We have two cases: one with the convex lens in air and one with the convex lens immersed in water. cylinder shaped floor lamps